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-0.4x^2+100x+250=0
a = -0.4; b = 100; c = +250;
Δ = b2-4ac
Δ = 1002-4·(-0.4)·250
Δ = 10400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{10400}=\sqrt{400*26}=\sqrt{400}*\sqrt{26}=20\sqrt{26}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-20\sqrt{26}}{2*-0.4}=\frac{-100-20\sqrt{26}}{-0.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+20\sqrt{26}}{2*-0.4}=\frac{-100+20\sqrt{26}}{-0.8} $
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